Anhelina Kalinina defeated Petra Kvitova in two sets (7-5, 6-4) in her Australian Open second round duel.
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A very attractive match at the John Cain Arena on a day that started with just a handful of duels and indoors due to the persistent rain in Melbourne. Peter Kvitov She entered the tournament as the favorite, starting the tournament as the fifteenth seed, looking for another win after a solid debut against Belgium’s Alison Van Uytvanck, whom she defeated in straight sets. The Czech is looking to stand out again at the Australian Open after reaching the 2019 final.
For him Anhelina Kalinina wanted to sign the biggest surprise in the women’s draw so far, continuing her positive run after a remarkable performance in the first round, losing just four games to American Coco Vandeweghe.
The first face-off between the two players since the Ukrainian went through when they were supposed to meet before their match at the last US Open.
Kvitova says goodbye in Australia
Kalinina started the match with a break opportunity, but was unable to hit the break. Later, the same situation would happen, but in favor of the Czech Republic, with the same resolution. The Ukrainian took advantage at the key moment of the ninth game and went 5-4. Although Kvitova recovered the break immediately, the European took yet another opportunity to take a now, yes, decisive advantage. Kalinina won the first set 7-5.
The pressure mounted on the two-time Grand Slam champion, who struggled to hold serve game after game. Despite resisting throughout the set, Kalinina managed to break Kvitova’s serve in the ninth game to be on the verge of victory. In the end, the Ukrainian decided the story with a decisive 6-4.
